Question #200717

Calculate the first four moments about the mean from the following frequency distribution.

          Also calculate the Moment Ratios b1 and  b2.                                               

Groups

2------4

4-------6

6------8

8-----10

10----12

12----14

14----16

16----18

18----20

Frequency

18

24

47

80

102

66

40

21

15


1
Expert's answer
2021-05-31T16:29:06-0400

The first central moment m1 is always zero.


The second central moment is:

m2=1Nfi(xix)2m_2=\frac{1}{N}\sum f_i(x_i-\overline{x})^2

where fi is frequency,

xi={3,5,7,9,11,13,15,17,19}x_i=\{3,5,7,9,11,13,15,17,19\}


The third central moment is

m3=1Nfi(xix)3m_3=\frac{1}{N}\sum f_i(x_i-\overline{x})^3


The fourth central moment is

m3=1Nfi(xix)4m_3=\frac{1}{N}\sum f_i(x_i-\overline{x})^4


Using online calculator vrcacademy.com, we get:

Number of observations:

N=413N=413

Mean of X values:

x=10.76\overline{x}=10.76


m2=13.76m_2=13.76

m3=3.17m_3=3.17

m4=526.43m_4=526.43


Moment Ratios:

skewness:

b1=1Nσ3(xix)3b_1=\frac{1}{N\sigma^3}\sum (x_i-\overline{x})^3

kurtosis

b2=1Nσ4(xix)4b_2=\frac{1}{N\sigma^4}\sum (x_i-\overline{x})^4

where σ\sigma is standard deviation.


Using online calculator www.socscistatistics.com, we get:

b1=0b_1=0

b2=1.2b_2=-1.2


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