Question #20069

Consider the probability experiment of a sequence of independent trials (number of trials n=11), each trial is the rolling of a pair of 6-sided dice. suppose a random event A is the sum of the roll is an odd number and a random variable represents the number of successes that occur in the n trials. Find the probability of the success for a single trial, find the probability mass function Pn(m), m=1,n, find the mathematical expectation and variance of the random variable

Expert's answer

Conditions

Consider the probability experiment of a sequence of independent trials (number of trials n=11n = 11 ), each trial is the rolling of a pair of 6-sided dice. Suppose a random event A is the sum of the roll is an odd number and a random variable represents the number of successes that occur in the n trials. Find the probability of the success for a single trial, find the probability mass function Pn(m)P_n(m) , m=1,nm = 1, n , find the mathematical expectation and variance of the random variable

Solution

Let's random variable ξ\xi is represents the number of successes that occur in the n trials.

Look at the table below:



Using Bernoulli's formula to find pp for each number of success.


Pn,m=CnmpmqnmP _ {n, m} = C _ {n} ^ {m} p ^ {m} q ^ {n - m}P11,0=C120p0q11=11!10!0!(12)11=0.00049P _ {1 1, 0} = C _ {1 2} ^ {0} p ^ {0} q ^ {1 1} = \frac {1 1 !}{1 0 ! 0 !} \left(\frac {1}{2}\right) ^ {1 1} = 0. 0 0 0 4 9P11,1=C121p1q10=0.00537P _ {1 1, 1} = C _ {1 2} ^ {1} p ^ {1} q ^ {1 0} = 0. 0 0 5 3 7P11,11=0.00049P _ {1 1, 1 1} = 0. 0 0 0 4 9M(ξ)=i=011ξixi=5.5M (\xi) = \sum_ {i = 0} ^ {1 1} \xi_ {i} x _ {i} = 5. 5D(ξ)=M(ξ2)(M(ξ))2D (\xi) = M \left(\xi^ {2}\right) - \left(M (\xi)\right) ^ {2}D(ξ)=335.52=2,75D (\xi) = 3 3 - 5. 5 ^ {2} = 2, 7 5

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS