Question #19987

Use the given degree of confidence and sample data to construct a confidence interval for the population means. A random sample of 15 light bulbs had a mean life of 548 hours and a sample standard deviation of 29 hours. Find a 90 percent confidence interval for the mean life, μ, of all light bulbs of this type.

Expert's answer

Conditions

Use the given degree of confidence and sample data to construct a confidence interval for the population means. A random sample of 15 light bulbs had a mean life of 548 hours and a sample standard deviation of 29 hours. Find a 90 percent confidence interval for the mean life, μ\mu, of all light bulbs of this type.

Solution

0.9=P(1.65Xˉμσn1.65)0.9 = P(-1.65 \leq \frac{\bar{X} - \mu}{\frac{\sigma}{\sqrt{n}}} \leq 1.65)


Where:

1.65 – the value of cumulative distribution function at a point p=0.9p=0.9

Xˉ\bar{X} – sample mean

μ\mu – distribution mean

σ\sigma – standard deviation

nn – sample size.

The confidence interval is:


(Xˉ1.65σnμXˉ+1.65σn)=(5481.652915μ548+1.652915)\left(\bar{X} - 1.65 \frac{\sigma}{\sqrt{n}} \leq \mu \leq \bar{X} + 1.65 \frac{\sigma}{\sqrt{n}}\right) = \left(548 - 1.65 \frac{29}{\sqrt{15}} \leq \mu \leq 548 + 1.65 \frac{29}{\sqrt{15}}\right)535,64518μ560,35482535,64518 \leq \mu \leq 560,35482

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