A hot line with a full free number receives an average of 4 calls per hour for any given hour. Find the probability that it will receive exactly 5 calls
P(X=x)=e−λλxx!λ=4P(X=5)=e−4455!=0.1563P(X=x) = \frac{e^{-λ}λ^x}{x!} \\ λ=4 \\ P(X=5) = \frac{e^{-4}4^5}{5!} = 0.1563P(X=x)=x!e−λλxλ=4P(X=5)=5!e−445=0.1563
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