Answer to Question #198572 in Statistics and Probability for Kobz

Question

Probability Distribution Problem

1.) I throw a die and get P1.00 if it is showing 1, get P2.00 if it is showing 2, P3.00 if it

is showing 3, P4.00 if it is showing 4, P5.00 if it is showing 5, and get P6.00 if it is

showing 6. What is the amount of money I can expect if I throw it 100 times?

complete solution

Answer 1

For one throw:

$E(X)=\frac{1}{6}(1+2+3+4+5+6)=\frac{21}{6}=P3.5.$

For 100 throws:

$E(X)=3.5*100=P350.$