2. An ordinary die is rolled once. Find the probability that
i. An even number occurs
ii. A number greater than 4 occurs
Solution:
S={1,2,3,4,5,6}S=\{1,2,3,4,5,6\}S={1,2,3,4,5,6}
(i) Let E be the event of getting an even number.
E={2,4,6}E=\{2,4,6\}E={2,4,6}
P(E)=36=12P(E)=\dfrac{3}{6}=\dfrac{1}{2}P(E)=63=21
(ii) Let G be the event of getting a number greater than 4.
G={5,6}G=\{5,6\}G={5,6}
P(G)=26=13P(G)=\dfrac{2}{6}=\dfrac{1}{3}P(G)=62=31
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