How many workers have salary above $2675 in the distribution whose average salary is $2400 and standard deviation is $100 and the number of workers in the factory is 15000. If the salary of workers follows the normal law?
Solution:
Given, "\\mu=\\$2400,\\sigma=\\$100,n=15000"
"X\\sim N(\\mu,\\sigma)"
"P(X>2675)=P(z>\\dfrac{2675-2400}{100})=P(z>2.75)=1-P(z\\le2.75)\n\\\\=1-0.99702=0.00298"
Now, the number of workers having salary greater than $2675"=0.00298\\times15000=44.7\\approx44"
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