what is the probability that a market inspector will discover at most three violations of the public health code
The probability that a market inspector will discover at most three violations of the public health code =P(X≤3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)= P(X \le 3) = P(X=0)+P(X=1)+P(X=2)+P(X=3)=P(X≤3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)
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