It has been found that 2 % of the tools produced by a certain machine are defective . What is the probability that in a shipment of 4 0 0 such tools , 3 % or more will be prove defective ?
While the Binomial is technically the right way to do this, for sufficiently large n and small p, the Poisson distribution offers an approximation that’s easier to compute.
So 2% of 400 = 8
So the question is, given an Poisson distribution of defectives with average =8,
probability we get 12 or more defective, or
1-cumulative probability of getting 11 or less defective
In excel use =1-poisson.dist(11, 8, TRUE)=11.2%
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