Question #194978

An electric bulb company manufacturing company claims that the bulbs produced by them have a mean life of 1250 hours. A random sample of 25 bulbs gives an average life of 1290 hours with standard deviation of of 110 hours. Use 5% level of significance and test the claim if bulb life follows is 1250 hours. ( t 0.025 (24) =2.064).

1
Expert's answer
2021-05-21T02:44:02-0400

H0:μ=1250hrs.H_0 : \mu = 1250hrs.


H1:μ1250H_1 : \mu \ne 1250

Since α=0.05\alpha = 0.05 and the test is a two tailed test, the critical values are -1.96 and 1.96


z can be calculated as z=xˉμσn=1290125011025=1.82z = \dfrac{\bar x- \mu}{\dfrac{\sigma}{\sqrt{n}}} = \dfrac{1290-1250}{\dfrac{110}{\sqrt{25}}} = 1.82

The vale of α\alpha is less than the calculated value of z. Hence, Null Hypothesis is accepted.



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