Answer to Question #194547 in Statistics and Probability for FaynuseD

Question #194547

Suppose we would like to gauge voters’ preferences for the President of Mars’ election. In an exit poll with a random sample of 120 voters, 30 voted for Mark Zuckerberg and 90 voted for Elon Musk. For the following, report your answers in 3 decimal places.

(a) Construct a 98% Wilson score confidence interval for Mars’ population proportion p supporting Elon Musk.

(b) Construct a 98% Wald confidence interval for p.

(c) Explain why Wald confidence intervals can have lower coverage in practice when compared to Wilson score confidence intervals


1
Expert's answer
2021-05-21T03:00:01-0400

We have given that,

With a random sample of 120 voters, 30 voted for Mark Zuckerberg and 90 voted for Elon Musk


p1=30120=0.25p_1 = \dfrac{30}{120} = 0.25

p2=90120=0.75p_2 = \dfrac{90}{120} = 0.75

a.) CI=p1±zp1(1p1)nCI= p_1 \pm z\sqrt{\dfrac{p_1(1-p_1)}{n}}


CI=0.25±2.330.25×0.75120CI = 0.25 \pm2.33 \sqrt{\dfrac{0.25 \times 0.75}{120}}


CI=0.25±0.092CI = 0.25 \pm 0.092


b.) CI=p2±zp2(1p2)nCI= p_2 \pm z\sqrt{\dfrac{p_2(1-p_2)}{n}}


CI=0.75±2.330.25×0.75120CI = 0.75 \pm2.33 \sqrt{\dfrac{0.25 \times 0.75}{120}}

CI=0.75±0.092CI = 0.75 \pm 0.092


c.) We can clearly see that wald confidence interval have lower average coverage because the proportion for the wald's score is more as compared to wilson.




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