Answer to Question #193888 in Statistics and Probability for Jack lakos

Question

1. A carton of 24 light bulbs includes two that are defecetive. If two of the bulbs are chosen at random, what are the probabilities that

a Neither bulb will be defective

b One of the bulbs will be defective

c Both bulbs will be defective

Answer 1

a)

$P=\frac{22}{24}\cdot\frac{21}{23}=\frac{77}{92}$

b)

$P=\frac{22}{24}\cdot\frac{2}{23}=\frac{11}{138}$

c)

$P=\frac{2}{24}\cdot\frac{1}{23}=\frac{1}{276}$