Question #193710

A random sample of n=70 measurements is obtained from a population with a mean 200 and standard deviation of 50.describe the sampling for the sample means by computing

Expert's answer

The Central Limit Theorem

For samples of size 30 or more, the sample mean is approximately normally distributed, with mean μXˉ=μ\mu_{\bar{X}}=\mu and standard deviation σXˉ=σ/n,\sigma_{\bar{X}}=\sigma/\sqrt{n}, where nn  is the sample size.

The larger the sample size, the better the approximation.


XˉN(μ,σ2/n)\bar{X}\sim N(\mu, \sigma^2/n)

Given μ=200,σ=50,n=70.\mu=200, \sigma=50, n=70.


The distribution of the sample mean is normal with mean μXˉ=μ=200\mu_{\bar{X}}=\mu=200 and standard deviation σXˉ=σ/n=50/70\sigma_{\bar{X}}=\sigma/\sqrt{n}=50/\sqrt{70}


XˉN(200,502/70)\bar{X}\sim N(200, 50^2/70)


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