Question #192537

You 

will combine two numbers from 0 to 9. One entry will win PHP 6000, out of 100 total entries, if 

you match the last two digits of the final score in a basketball game. Let X be the net gain from 

the purchase of one entry. What is the mean or the expected value of a person who buys a ticket? 

Illustrate by constructing a probability distribution. 


Expert's answer

Total number of ways in which we can choose two numbers =10C2=45= ^{10}C_2 = 45

One entry will win PHP6000

Probability that will win the entry  =45100=0.45= \dfrac{45}{100} = 0.45

Probability that does not win =55100=0.55= \dfrac{55}{100} = 0.55

Probability distribution can be given as,



Expected value of person who buys a ticket =0.45×6000+0.55×0=2700= 0.45 \times 6000 + 0.55 \times 0 = 2700

Expected value = 2700


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