A local paper claims the proportion of college students who own a car is 38%. In a sample of 275 college students, what is the probability that more than 116 will own a car?
"p = 0.38 \\\\\n\nq = 0.62 \\\\\n\nn = 275"
Using binomial distribution:
Mean:
"\\mu = n \\times p = 275 \\times 0.38 = 104.5"
Standard deviation:
"\\sigma = \\sqrt{n \\times p \\times q} = \\sqrt{275 \\times 0.38 \\times 0.62} = 8.05 \\\\\n\nP(X>116) = 1 -P(X<116) \\\\\n\n= 1 -P(Z< \\frac{116-104.5}{8.05}) \\\\\n\n= 1 -P(Z<1.428) \\\\\n\n= 1 -0.9233 \\\\\n\n= 0.0767"
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