Question

Suppose we have the following data:

30

79

59

65

40

64

52

53

57

39

61

47

50

60

48

50

58

67

Suppose the number of nonoverlapping classes is determined to be 5. 

 

What is the mean and sample variance for this data?

Answer 1

The distribution is-

Mean $\bar{x}=\dfrac{\sum xf}{\sum f}=\dfrac{970}{18}=53.88$

Sample Variance $=\dfrac{\sum (x-\bar{x})^2}{N-1}=\dfrac{1075.678}{18-1}=63.275$