Answer to Question #191273 in Statistics and Probability for Andin Anita

Question #191273

Suppose we have the following data:

30

79

59

65

40

64

52

53

57

39

61

47

50

60

48

50

58

67

Suppose the number of nonoverlapping classes is determined to be 5. 

 

What is the mean and sample variance for this data?


1
Expert's answer
2021-05-12T03:52:25-0400

The distribution is-




Mean xˉ=xff=97018=53.88\bar{x}=\dfrac{\sum xf}{\sum f}=\dfrac{970}{18}=53.88


Sample Variance =(xxˉ)2N1=1075.678181=63.275=\dfrac{\sum (x-\bar{x})^2}{N-1}=\dfrac{1075.678}{18-1}=63.275


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