Question #19124

Independent Samples t-test

Is there any evidence that leadership style (as measured by the amount of controlling behavior) differs between principals in urban and rural areas in Oromia? Data are provided in a Table below.
Urban
Mean = 78.6 Standard deviation = 16.70 N= 9
Rural
Mean = 69.10 Standard deviation = 19.31 N= 10

Expert's answer

Conditions

Independent Samples t-test

Is there any evidence that leadership style (as measured by the amount of controlling behavior) differs between principals in urban and rural areas in Oromia? Data are provided in a Table below.

Urban

Mean = 78.6 Standard deviation = 16.70 N= 9

Rural

Mean = 69.10 Standard deviation = 19.31 N= 10

Solution

For this test, the null hypothesis is that the means of samples are equal:


H0:M1=M2H_0: M_1 = M_2Hα:M1M2H_\alpha: M_1 \neq M_2t=Xˉ1Xˉ2SX2X31n1+1n2,t = \frac{\bar{X}_1 - \bar{X}_2}{S_{X_2 X_3} \sqrt{\frac{1}{n_1} + \frac{1}{n_2}}},SX2X3=12(SXˉ12+SXˉ22)S_{X_2 X_3} = \sqrt{\frac{1}{2} \left(S_{\bar{X}_1}^2 + S_{\bar{X}_2}^2\right)}SXˉ12=i=16(X1Xˉ1)2nS_{\bar{X}_1}^2 = \frac{\sum_{i=1}^{6} (X_1 - \bar{X}_1)^2}{n}SXˉ22=i=16(X2Xˉ2)2nS_{\bar{X}_2}^2 = \frac{\sum_{i=1}^{6} (X_2 - \bar{X}_2)^2}{n}


For this example:


t=1.145347t = 1.145347


The degrees of freedom:


k=9+102=17k = 9 + 10 - 2 = 17


For these degrees of freedom the t-criteria value is:

2.1098- for p=0.95

We can make a conclusion, that with probability 95% there is no difference between 2 groups. H0 is approved

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