The events for the question are as follows:
F=Eventwheretheadultisfemale
L=Eventwheretheadultislefthanded
FL=Eventwheretheadultisandlefthandedfemale
To find the probability of at least one of the two joint events we add the probabilities of these two events excluding the probability of their co-occurrence.
P(ForL)=P(F)+P(L)−P(FL)
Where:
P(F) =ProbabilityofeventF=0.526
P(L)=ProbabilityofeventL=0.095
P(FL) =ProbabilityofeventFandL=0.053
P(ForL)=0.526+0.095−0.053
P(ForL)=0.568
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