Find the area under the standard normal curve than z=0.5
So P(Z>0.5)=P(0<z<∞)−P(0<z<0.5)=0.5−0.19146=0.30854P(Z>0.5)=P(0<z<\infty)-P(0<z<0.5)=0.5-0.19146=0.30854P(Z>0.5)=P(0<z<∞)−P(0<z<0.5)=0.5−0.19146=0.30854
Area under normal curve of (z>0.5) is 0.30854.
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