Question

If a bag contains errors in 4 red, 5 blue and 4 green and 2 yellow balls. A kid randomly selects 6 balls without replacement. what is the probability that exactly 3 of the selected balls are blue?

Answer 1

Red balls = 4

Blue balls = 5

Green balls = 4

Yellow balls = 2

A kid randomly selects 6 balls without replacement.

We have to select exactly 3 balls.

No. of ways of selecting 3 balls from 15 balls = $^{15}C_3$

Then, the probability that exactly 3 of the selected balls are blue $= \dfrac{^{10}C_3 \times ^5C_3}{^{15}C_3}$