Determine the value c so that each of the following functions can serve as a probability distribution of the discrete random variable X:
(a) f(x) = c(x2 + 4), for x = 0, 1, 2, 3;
Given that,
f(x)=c(x2+4)f(x) = c(x^2+4)f(x)=c(x2+4) x=0,1,2,3x=0,1,2,3x=0,1,2,3
We know,
∑x=03f(x)=1\sum_{x=0}^{3}f(x) = 1∑x=03f(x)=1
c(4)+c(5)+c(8)+c(3)=1c(4)+c(5)+c(8)+c(3) = 1c(4)+c(5)+c(8)+c(3)=1
30c=130c = 130c=1
Hence, c=130c = \dfrac{1}{30}c=301
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