Question #189364

The weights of a women population are normally distributed with mean 60kg and standard deviation 5kg. Find the probability that the weight of a woman chosen at random is more than

65kg.


1
Expert's answer
2021-05-07T12:38:22-0400

To determine the probability of making options from random choices, the following expression is utilized: XN(μ,σ2)henceZ=XuσN(0,1)X-N\left(\mu ,\:\sigma ^2\right)\:hence\:Z=\frac{X-u}{\sigma }-N\left(0,\:1\right) provided that weightWN(60,52)W-N\left(60,\:5^2\right) then Z=W605N(0,1)Z=\frac{W-60}{5}-N\left(0,\:1\right)\:


To calculate P(W>65)P\left(W>65\right)

P(W>65)=P(W605>65605)P\left(W>65\right)\:=P\left(\frac{W-60}{5}>\frac{65-60}{5}\right)

=P(Z>1)=P\left(Z>1\right)

=10.9772=1-0.9772

=0.0228=0.0228\:


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