assign probability values P(X) to each of the random variable
Let X be the outcome of the roll of a die.
Then X is a random variable.
Its possible values are 1, 2, 3, 4, 5, and 6
Each of these possible values has probability
P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=16P(1)=P(2)=P(3)=P(4)=P(5)=P(6)= \dfrac{1}{6}P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=61
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