Find the area under normal curve from z = -2.83 to z= -0.82.
P(−2.83<Z<−0.82)=P(Z<−0.82)−P(Z<−2.83)=P(-2.83<Z<-0.82)=P(Z<-0.82)-P(Z<-2.83)=P(−2.83<Z<−0.82)=P(Z<−0.82)−P(Z<−2.83)=
=P(Z<2.83)−P(Z<0.82)=0.9977−0.7939=0.2038.=P(Z<2.83)-P(Z<0.82)=0.9977-0.7939=0.2038.=P(Z<2.83)−P(Z<0.82)=0.9977−0.7939=0.2038.
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