Question #189217

Let B be the number of boys in a family of 4 children

a) construct the probability distribution for the random variable B.


1
Expert's answer
2021-05-07T11:52:14-0400

b = boys

g = girls


Sample space -{ bbbb,bbbg,bbgb,bbgg,bgbb,bgbg,bggb,bggg,gbbb,gbbg,gbgb,gbgg,ggbb,ggbg,gggb,gggg}


The possible outcomes for B are 0,1,2,3,4.0, 1, 2,3,4.


P(X=0)=116P(X=1)=416=14P(X=2)=616=38P(X=3)=416=14P(X=4)=116P(X=0)=\dfrac{1}{16}\\[9pt] P(X=1)=\dfrac{4}{16}=\dfrac{1}{4}\\[9pt] P(X=2)=\dfrac{6}{16}=\dfrac{3}{8}\\[9pt] P(X=3)=\dfrac{4}{16}=\dfrac{1}{4}\\[9pt] P(X=4)=\dfrac{1}{16}


The probability distribution of B is-






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