Answer to Question #188808 in Statistics and Probability for Jessica

Question #188808

 In Pleasantville about 25% of the residents prefer vanilla ice cream over other flavors. A certain day, 175 residents of Pleasantville went to an ice cream store, what is the probabil- ity that 50 or more will get vanilla ice cream?


1
Expert's answer
2021-05-07T14:17:34-0400

p = 0.25

q = 0.75

n = 175

Using binomial distribution:

Mean:

μ=n×p=175×0.25=43.75\mu = n \times p = 175 \times 0.25 = 43.75

Standard deviation:

σ=n×p×q=175×0.25×0.75=5.728\sigma = \sqrt{n \times p \times q} = \sqrt{175 \times 0.25 \times 0.75} = 5.728

P(X50)=1P(X<49.5)=1P(Z<49.543.755.728)=1P(Z<0.197)=10.5780=0.422P(X≥50) = 1 -P(X<49.5) \\ = 1 -P(Z< \frac{49.5 -43.75}{5.728}) \\ = 1 -P(Z<0.197) \\ = 1 -0.5780 \\ = 0.422


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