Question 18748 Hi, the topic is Probability Density Function of a random variable.
For each of the following, find the constant c so that p(x) satisfies the condition of being a probability density function of a random variable X: I. p(x)=c(2/3)x, x∈N II. p(x)=cx, x∈{1,2,3,4,5,6}
I've been figuring this for couple of days. Solution. In fact, p(x) is rarely called probability density function. It is just distribution of a r.v., p(x)=P(X=x).
We are to verify two conditions: 1) p(x)≥0 and ∑x∈Np(x)=1. So,
a) c>0 and ∑x∈Np(x)=c∑x∈N(2/3)x=c1/32/3=2c=1, thus c=1/2. Remark: this is the case when 0∈/N(2 definitions of natural numbers are used in mathematics.), if 0∈N, then ∑x∈Np(x)=c∑x∈N(2/3)x=3c, thus c=1/3.
b) ∑x∈{1,2,3,4,5,6}cx=c26⋅7=21c, thus c=1/21