Question #1872
A problem in mathematics is given to three students A, B and C whose chances of solving it are 1/2, 3/4 and 1/4 respectively. What is the probability that the problem will be solved if all of them try independently.
Expert's answer
The probability that the problem is not solved by any of them:
(1 - P(A))*(1 - P(B))* (1 - P(C)) = (1 - 1/2)(1 - 3/4)(1 - 1/4) = 1/2*1/4*3/4 = 3/32
Hence, the probability that the problem will be solved is
1 - 3/32 = 29/32.
(1 - P(A))*(1 - P(B))* (1 - P(C)) = (1 - 1/2)(1 - 3/4)(1 - 1/4) = 1/2*1/4*3/4 = 3/32
Hence, the probability that the problem will be solved is
1 - 3/32 = 29/32.
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