Question #187117

Find margin of error and confidence interval for the population mean µ of the college graduates who have taken the statistics course if average value for sample of 25 objects is 52,620 and sample standard deviation S=10,700 . Use 95% confidence interval. (Use t-distribution)



1
Expert's answer
2021-05-07T10:29:03-0400

Given, n=25,μ=56250,σ=10,700n=25, \mu=56250,\sigma=10,700


α=0.05,tα2=t0.025=2.064\alpha=0.05, t_{\frac{\alpha}{2}}=t_{0.025}=2.064


Critical value is 2.064.


Margin of Error (MOE)=critical value ×\times population standard deviation


=2.064×1070025=2.064\times \dfrac{10700}{\sqrt{25}}


=2.064×107005=4416.96=2.064\times \dfrac{10700}{5}=4416.96


Confidence Interval =μ±MOE=52620±4416.96=(48233.04,57066.9)=\mu\pm MOE=52620\pm 4416.96=(48233.04,57066.9)


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