Answer to Question #187046 in Statistics and Probability for sphoorthi

Question

Let X

X be N(5,4)

N(5,4) and P(|X−5|>c)=0.01

P(|X−5|>c)=0.01. Then the value of c

c is most approximately equal to

Answer 1

Given,

X~N(5,4)

Given distribution is a normal distribution with $\mu=5,\sigma=4$

Also, $P(|X-5|>c)=0.01$

$P(|X-5|<c)=1-0.01=0.99$

Hence, The value of c from the table is $2.3$