Consider a population consisting of the values (1, 3, 8), n= 2 with replacement.
Solution:
Possible sample of size 2 with replacement"=\\{(1,3)(3,8)(1,8),(1,1),(3,3),(8,8)\\}"
Sample means for these samples"=\\{2,5.5,4.5,1,3,8\\}"
(1): Mean of sample means"=(2+5.5+4.5+1+3+8)\/6=4"
Population mean"=(1+3+8)\/3=4"
Population variance",\\sigma^2=\\dfrac{(1-4)^2+(3-4)^2+(8-4)^2}{3}=\\dfrac{26}3"
(2): The variance of the sampling distribution of means",\\sigma_x^2=\\dfrac{\\sigma^2(N-n)}{n(N-1)}"
"=\\dfrac{\\dfrac{26}3(3-2)}{2(3-1)}=\\dfrac{13}6"
(3): The standard deviation of the sampling distribution",\\sigma_x=\\sqrt{\\dfrac{13}6}"
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