Compute for the standard error of the mean given the population variance and the sample size. Show your complete solutions.3.1. π" = 20.50; π = 33.2. π" = 13.18; π = 5
3.1 Οβ²β²=20.5,n=3\sigma''=20.5, n=3Οβ²β²=20.5,n=3
standard error of the mean =Οβ²β²n=\sqrt{\sigma'' n}=Οβ²β²nβ
=20.5Γ3=61.5=7.84=\sqrt{20.5\times 3} \\=\sqrt{61.5}=7.84=20.5Γ3β=61.5β=7.84
3.2 Οβ²β²=13.18,n=5\sigma''=13.18, n=5Οβ²β²=13.18,n=5
=13.18Γ5=65.9=8.11=\sqrt{13.18\times 5}\\ =\sqrt{65.9}=8.11=13.18Γ5β=65.9β=8.11
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