Question #18509

A can hit target 4 times in 5 shots, B can hit 2 times in 4 shots and C can hit 2 times in 4 shots.Find the probability that
(i) 2 shots hit.
(ii) at least two shots hit.

Expert's answer

Conditions

A can hit target 4 times in 5 shots, B can hit 2 times in 4 shots and C can hit 2 times in 4 shots. Find the probability that

(i) 2 shots hit.

(ii) at least two shots hit.

Solution

The probabilities to hit a target for A,B,C are:


45,12,12\frac{4}{5}, \frac{1}{2}, \frac{1}{2}


If everyone shots only once, then the probability of 2 shots hit is:


451212+451212+151212=920\frac{4}{5} \cdot \frac{1}{2} \cdot \frac{1}{2} + \frac{4}{5} \cdot \frac{1}{2} \cdot \frac{1}{2} + \frac{1}{5} \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac{9}{20}


The probability of at least 2 shots hit is:


451212+451212+151212+451212=1320\frac{4}{5} \cdot \frac{1}{2} \cdot \frac{1}{2} + \frac{4}{5} \cdot \frac{1}{2} \cdot \frac{1}{2} + \frac{1}{5} \cdot \frac{1}{2} \cdot \frac{1}{2} + \frac{4}{5} \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac{13}{20}


Answer: (i) 920\frac{9}{20}, (ii) 1320\frac{13}{20}

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