For a t-distribution with 14 degrees of freedom, find the value of t such that the area between –t and t is 0.90.
Given, Degree of freedom=14
"P(-t<x<t))=0.90"
"2P(0<x<t)=0.90\\Rightarrow P(0<x<t)=0.45"
At 14 degree of freedom The value of t is 1.66.
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