Question

For a t-distribution with 14 degrees of freedom, find the value of t such that the area between –t and t is 0.90. 

Answer 1

Given, Degree of freedom=14

$P(-t<x<t))=0.90$

$2P(0<x<t)=0.90\Rightarrow P(0<x<t)=0.45$

At 14 degree of freedom The value of t is 1.66.