Question

If a random variable is normally distributed with mean 4.35 and standard deviation 0.59, what is the probability that this random variable will take on values more than 5.2?

Answer 1

$\mu = 4.35 \\ \sigma = 0.59 \\ P(X>5.2) = 1 -P(X<5.2) \\ = 1 -P(Z< \frac{5.2-4.35}{0.59}) \\ = 1 -P(Z<1.44) \\ = 1 -0.9250 \\ = 0.0750$