A binary experiment is repeated 900 times. What is the probability that there will be at least 495 successes if the success probability is 0.5?
Let X denote the number of successes. Then X\sim Bin(n=900,p=0.5)
Using Normal approximation to Binomial distribution,
"X\\sim N(\\mu=n \\times p=450,\\sigma^{2}=n \\times p(1-p)=225)"
Required probability "= P(X\\geq 495)=P(X>495.5)"
(Due to continuity correction as a result of using Normal approximation for Binomial distribution)
"=P(Z>\\frac{495.5-450}{\\sqrt{225}}) \\\\\n\n=P(Z>3.03) \\\\\n\n=1-P(Z<3.03) \\\\\n\n=1-0.9987 \\\\ \n\n=0.0013"
Comments
Leave a comment