Answer to Question #181511 in Statistics and Probability for Vinnakota Chandra Sekhar

Question #181511

A fair die is rolled till all the numbers 1, 2, ..., 6 appear on the top. What is the probability that at least 7 rolls are needed?

Expert's answer

"\\frac{6\\times6!+15\\times6!}{6^7} = \\frac{21\\times6!}{6^7} = 0.054 =" 5.4%

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