Five hundred children participated in a field demonstration. Their heights averaged is 110 cm with a standard deviation of 6 cm. How many children have heights between 98 cm and 104 cm?
mean "= \\mu = 110"
standard deviation "= \\sigma = 6"
"P(98<x<104) = P(\\frac{98-110}{6}<Z< \\frac{104-110}{6}) \\\\\n\n= P(-2 <Z< -1) \\\\\n\n= P(Z< -1) -P(Z< -2) \\\\\n\n= 0.1586 \u2013 0.0227 \\\\\n\n= 0.1359"
= 13.59 %
"500 \\times 0.1359 = 68" children have heights between 98 cm and 104 cm
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