Question #181319

Answer the question below


In a math test, the mean score is 45 and the standard deviation is 4. Assuming normality, what is the probability that the score will lie: 

If the score is above 58

If the score is below 49

If the score is below 68

If the score is above 55

If the score is above 38


Expert's answer

μ=45σ=4P(X>58)=1P(X<58)=1P(Z<58454)=1P(Z<3.25)=10.9994=0.0006P(X<49)=P(Z<49454)=P(Z<1)=0.8413P(X<68)=P(Z<68454)=P(Z<5.75)=0.9999P(X>55)=1P(X<55)=1P(Z<55454)=1P(Z<2.5)=10.9937=0.0063P(X>38)=1P(X<38)=1P(Z<38454)=1P(Z<1.75)=10.04006=0.95994\mu = 45 \\ \sigma = 4 \\ P(X>58) = 1 -P(X<58) \\ = 1 -P(Z< \frac{58-45}{4}) \\ = 1 -P(Z<3.25) \\ = 1 -0.9994 \\ = 0.0006 \\ P(X<49) = P(Z< \frac{49-45}{4}) \\ = P(Z< 1) \\ = 0.8413 \\ P(X<68) = P(Z< \frac{68-45}{4}) \\ = P(Z< 5.75) \\ = 0.9999 \\ P(X>55) = 1 -P(X<55) \\ = 1 -P(Z< \frac{55-45}{4}) \\ = 1 -P(Z<2.5) \\ = 1 -0.9937 \\ = 0.0063 \\ P(X>38) = 1 -P(X<38) \\ = 1 -P(Z< \frac{38-45}{4}) \\ = 1 -P(Z< -1.75) \\ = 1 -0.04006 \\ = 0.95994


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