The random variable Y has the distribution function
F(y)= 0 y<1
ln 0<y<1
1y>1
find the following, i) P( y>2) ii) P(2<y<2)
FY(y)={0if y≤0ln yif 0<y≤11if y>1F_Y(y) = \begin{cases} 0 &\text{if } y\leq0 \\ ln\ y &\text{if } 0< y\leq1 \\ 1 &\text{if } y>1 \\ \end{cases}FY(y)=⎩⎨⎧0ln y1if y≤0if 0<y≤1if y>1
i) P(Y>2)=1−P(Y≤2)=1−FY(2)=0P(Y>2)= 1-P(Y\leq2)=1-F_Y(2)=0P(Y>2)=1−P(Y≤2)=1−FY(2)=0
ii) P(1<Y<2)=FY(2)−FY(1)=1−ln1=1P(1<Y<2)=F_Y(2)-F_Y(1)=1-ln1=1P(1<Y<2)=FY(2)−FY(1)=1−ln1=1
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