Question #180526

Q3. a. If a random variable X has mean 3 and standard deviation 5, then find out the variance of a variable

Y=2X-5.

b. If each observation in the set of values (X, Y) is divided by 100, then find the correlation coefficient of

new data set?


1
Expert's answer
2021-04-14T07:39:58-0400

a. We use the linearity of a mean of random variables and receive: E[Y]=E[2X5]=2E[X]E[5]=2E[X]5=65=1E[Y]=E[2X-5]=2E[X]-E[5]=2E[X]-5=6-5=1.

We remind that the standard deviation squared is: σY2=E[(YE[Y])2]=E[Y22YE[Y]+(E[Y])2]=E[Y2]2(E[Y])2+(E[Y])2=E[Y2](E[Y])2=E[4X220X+25]1=4E[X2]20E[X]+24=4E[X2]+24203=4E[X2]+2460=4E[X2]36\sigma_Y^2=E[(Y-E[Y])^2]=E[Y^2-2YE[Y]+(E[Y])^2]=E[Y^2]-2(E[Y])^2+(E[Y])^2=E[Y^2]-(E[Y])^2=E[4X^2-20X+25]-1=4E[X^2]-20E[X]+24=4E[X^2]+24-20\cdot3=4E[X^2]+24-60=4E[X^2]-36

We find E[X2]E[X^2] from equality: 25=σX2=E[X2](E[X])2=E[X2]925=\sigma_X^2=E[X^2]-(E[X])^2=E[X^2]-9. We receive: E[X2]=34E[X^2]=34. Finally, we get: σY2=43436=100\sigma_Y^2=4\cdot34-36=100 and σY=10\sigma_Y=10.

Thus, the mean is 1 and the standard deviation is 10.

b. We remind that the formula for Pearson's correlation coefficient(when applied to sample) is:

rxy=i=0n(xixˉ)(yiyˉ)i=0n(xixˉ)2i=0n(yiyˉ)2r_{xy}=\frac{\sum_{i=0}^n(x_i-\bar{x})(y_i-\bar{y})}{\sqrt{\sum_{i=0}^n(x_i-\bar{x})^2}\sqrt{\sum_{i=0}^n(y_i-\bar{y})^2}}. As we can see from the formula, the coefficient will remain unchanged.


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