n= 1000, n= 60, mean = 75, standard deviation= 6, probability= p(x<76.5)
Here,
Mean μ=75Standard Deviation σ=6N=1000n=60Mean\ \mu=75\\Standard\ Deviation\ \sigma=6\\\\N=1000\\n=60Mean μ=75Standard Deviation σ=6N=1000n=60
z=x−μσ=76.5−756=0.25z=\dfrac{x-\mu}{\sigma}=\dfrac{76.5-75}{6}=0.25z=σx−μ=676.5−75=0.25
So, P(x<76.5)=P(z<0.25)=0.5987P(x<76.5)=P(z<0.25)=0.5987P(x<76.5)=P(z<0.25)=0.5987
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