A meeting of envoys was attended by 4 Koreans and 2 Filipinos. If three
envoys were selected at random one after the other, determine the values
of the random variable F representing the number of Filipinos.
F=0: p=46∗35∗24=15.F=0:\;p=\frac{4}{6}*\frac{3}{5}*\frac{2}{4}=\frac{1}{5}.F=0:p=64∗53∗42=51.
F=1: p=46∗35∗24+46∗25∗34+26∗45∗34=35.F=1:\;p=\frac{4}{6}*\frac{3}{5}*\frac{2}{4}+\frac{4}{6}*\frac{2}{5}*\frac{3}{4}+\frac{2}{6}*\frac{4}{5}*\frac{3}{4}=\frac{3}{5}.F=1:p=64∗53∗42+64∗52∗43+62∗54∗43=53.
F=2: p=26∗15∗44+26∗45∗14+46∗25∗14=15.F=2:\;p=\frac{2}{6}*\frac{1}{5}*\frac{4}{4}+\frac{2}{6}*\frac{4}{5}*\frac{1}{4}+\frac{4}{6}*\frac{2}{5}*\frac{1}{4}=\frac{1}{5}.F=2:p=62∗51∗44+62∗54∗41+64∗52∗41=51.
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Possible outcomes are 0, 1 and 2.
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Possible outcomes are 0, 1 and 2.
what are the posible outcomes?
A solution of the question has already been published.
Where is the answer?