We use Poisson's formula p(m)=m!λme−λ . In our case λ=2 .
a) Let's find the probabilities that 0, 1 and 2 errors will be made:
p(0)=0!20e−2=e−2;p(1)=1!21e−2=2e−2;p(2)=2!22e−2=2e−2
Then the probability that the secretary makes less than 3 errors is
p(x<3)=p(0)+p(1)+p(2)=5e−2
Whence the wanted probability, as the probability of the opposite event, is
p(x≥3)=1−p(x<3)=1−5e−2≈0.323
Answer: p(x≥3)≈0.323
b) Let's find the probabilities that 6, 7 and 8 errors will be made:
p(6)=6!26e−2=454e−2;p(7)=7!27e−2=3158e−2;p(8)=8!28e−2=3152e−2
Then wanted probability is
p(6≤x≤8)=p(6)+p(7)+p(8)=31538e−2≈0.0163
Answer: p(6≤x≤8)≈0.0163
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