Find the probability that the sum is as stated when a pair of dice is rolled. (Enter your answers as fractions.)
(a) odd or less than 5
Since each dice has 6 faces, the total number of outcomes is
"n = 6 \\cdot 6 = 36"
Let's list the favorable outcomes: (1,1), (1,2), (1,3), (1,4), (1,6), (2,1), (2,2), (2,3), (2,5), (3,1), (3,2), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,4), (5,6), (6,1), (6,3), (6,5).
Then the number of favorable outcomes "m = 22" . So, "p = \\frac{m}{n} = \\frac{{22}}{{36}} = \\frac{{11}}{{18}}" .
Answer: "p = \\frac{{11}}{{18}}"
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