The probability that a smoke alarm will function properly and sound an alarm in the presence of smoke is 0.8. You have 2 such alarms in your home and they operate independently.
The probability that neither sound an alarm in the presence of smoke
Let the two events:
P(A )= The probability that a smoke alarm will function properly and sound an alarm in the presence of smoke
P(B)= The probability that a smoke alarm will not function properly and sound an alarm in the presence of smoke
We are given
P(A) = 0.8
Therefore
P(B) = 1-0.8 = 0.2
Since the two events are independent, the probability that neither sound an alarm in the presence of smoke
P(B and B) = P(B) * P(B) = 0.2*0.2 = 0.04
Answer = 0.04
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