From a box containing 2 apples, 2 peaches and 2 oranges, 4 fruits are drawn at random. Let P be a random variable representing the number of oranges that occur. Construct a probability distribution.
Solution:
Number of apples = 2
Number of peaches = 2
Number of oranges = 2
Total fruits = 6
4 fruits are random.
Let P be the random variable representing the number of oranges that occur.
So, P = {0, 1, 2}
When P = 0,
"P(0)=\\dfrac{^2C_0\\times ^4C_4}{^6C_4}=\\dfrac1{15}"
When P = 1,
"P(1)=\\dfrac{^2C_1\\times ^4C_3}{^6C_4}=\\dfrac{2\\times 4}{15}=\\dfrac8{15}"
When P = 2,
"P(2)=\\dfrac{^2C_2\\times ^4C_2}{^6C_4}=\\dfrac{6}{15}=\\dfrac2{5}"
Required probability distribution is:
P P(P)
0 "\\dfrac1{15}"
1 "\\dfrac8{15}"
2 "\\dfrac2{5}"
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