Question #176078

From a box containing 2 apples, 2 peaches and 2 oranges, 4 fruits are drawn at random. Let P be a random variable representing the number of oranges that occur. Construct a probability distribution.


1
Expert's answer
2021-03-30T07:50:46-0400

Solution:

Number of apples = 2

Number of peaches = 2

Number of oranges = 2

Total fruits = 6

4 fruits are random.

Let P be the random variable representing the number of oranges that occur.

So, P = {0, 1, 2}

When P = 0,

P(0)=2C0×4C46C4=115P(0)=\dfrac{^2C_0\times ^4C_4}{^6C_4}=\dfrac1{15}

When P = 1,

P(1)=2C1×4C36C4=2×415=815P(1)=\dfrac{^2C_1\times ^4C_3}{^6C_4}=\dfrac{2\times 4}{15}=\dfrac8{15}

When P = 2,

P(2)=2C2×4C26C4=615=25P(2)=\dfrac{^2C_2\times ^4C_2}{^6C_4}=\dfrac{6}{15}=\dfrac2{5}

Required probability distribution is:

P P(P)

0 115\dfrac1{15}

1 815\dfrac8{15}

2 25\dfrac2{5}


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