Solution:
Given, "n=60, \\mu=192,\\sigma=43"
Mean of 60 sample means, "\\mu_{x}=\\mu=192"
Standard deviation of 60 sample means, "\\sigma_x=\\dfrac{\\sigma}{\\sqrt n}=\\dfrac{43}{\\sqrt {60}}\\approx5.551"
Thus, sampling distribution has "\\mu_{x}=192,\\sigma_x=5.551"
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