N=200, n=10
Here, N= 200
and, n= 10
Probability of head = 12\dfrac{1}{2}21
So, p=12 q=12p= \dfrac{1}{2} \ \ q= \dfrac{1}{2}p=21 q=21
So, Probability of getting head = 200C10(12)10(12)190^{200}C_{10}(\frac{1}{2})^{10}(\frac{1}{2})^{190}200C10(21)10(21)190
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