Question

How many arrangement are there of the letters DISAPPOINT?

Answer 1

10 is the total number of letters where 2 times P, 2 times I occurs in DISAPPOINT.

$\frac{10!}{2!2!} = \frac{2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9 \times 10}{2 \times 2} = 907200$